Remove Brackets containing Numbers with a simple criteria

heathball

Board Regular
Joined
Apr 6, 2017
Messages
130
Office Version
  1. 365
Platform
  1. Windows
I cannot find a way to do this> i hope someone can help.

this is an example, and there are lots of numbers that can apply.

The qualifying criteria is the number must end with "L", and there is a "-" placed between the number and the "L" after the removal of the brackets
Other numbers inside brackets, like (3.7) remain as they are.

The qualifiers each sit in one column, in cells with up to 500 other characters, and there are over 800,000 rows.

(16.45L)
needs to become
16.45-L

Jack went to Woolies and almost fainted when learning of the price of a (2.4L) milk carton.
needs to become
Jack went to Woolies and almost fainted when learning of the price of a 2.4-L milk carton.

-no spaces
-maximum of 2 decimals inside the brackets
-maximum number is 100

I imagine a helper column could assist if the task is not efficient on a large data set.

i could create a long vba code with a line for each number, but i suspect there is something possible, and it would be great if i could shorten the task - for future reference as well.
 

Excel Facts

Bring active cell back into view
Start at A1 and select to A9999 while writing a formula, you can't see A1 anymore. Press Ctrl+Backspace to bring active cell into view.
Would this work:
Excel Formula:
=SUBSTITUTE(A1,TEXTBEFORE(RIGHT(A1,LEN(A1)-SEARCH("(*.*L)",A1)+1)," ",1),SUBSTITUTE(TEXTJOIN("",,TEXTSPLIT(TEXTBEFORE(RIGHT(A1,LEN(A1)-SEARCH("(*.*L)",A1)+1)," ",1),{"(",")"})),"L","-L"))
 
Upvote 1
Solution
Hi Heathball, if (16.45l) was in B2 you could use =SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(B2,"(",""),")",""),"L","-L")
The first substitute finds the left bracket and replaces it with "" (nothing) =SUBSTITUTE( SUBSTITUTE( SUBSTITUTE(B2,"(","") ,")",""), "L","-L").
the 2nd substitute looks at the new data without the left bracket finds the right bracket and replaces it with "" (nothing) =SUBSTITUTE( SUBSTITUTE( SUBSTITUTE(B2,"(","") ,")",""), "L","-L").
The 3rd substitute looks at the new data without the left and right brackets, finds the "L" and replaces it with "-L" = SUBSTITUTE( SUBSTITUTE( SUBSTITUTE(B2,"(","") ,")",""), "L","-L").
Hope this helps
 
Upvote 0
hagia_sofia - there was a piece of information which i did not realise at first.
i see on many rows there is more than one instance of a qualifying number in brackets, and this code desld with the first instance.
But i can seperate this data, now that i have this formula, and get it done that way, so thanks again.

Peter Juhnke - thanks for writing that formula> i am having a look at it.
the 2nd line
i am not having any luck with it at the moment. But i am intrigued by it and thanks for explaining it well. I will keep tinkering with it for now

=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(b2,"(","") ,")",""),L,"-L").
 
Upvote 0
Try:
Book1
AB
1Jack went to Woolies and almost fainted when learning of the price of a (2.5L) milk carton.Jack went to Woolies and almost fainted when learning of the price of a 2.5-L milk carton.
2This string contains Jack (Josh) Smith. He bout (100.0L) of milkThis string contains Jack (Josh) Smith. He bout 100.0-L of milk
3Jack (nick name Joe) and Jill (nick name Jay) sold (56.5L) together.Jack (nick name Joe) and Jill (nick name Jay) sold 56.5-L together.
4Mya (Mira) Smith drank (56.8L) of juice, while Sam (Samuuel) drank only (2.0L) of juice.Mya (Mira) Smith drank 56.8-L of juice, while Sam (Samuuel) drank only 2.0-L of juice.
Sheet11
Cell Formulas
RangeFormula
B1:B4B1=LET(ts,TEXTSPLIT(A1," "), TEXTJOIN(" ",,IF(ISNUMBER(SEARCH(".",ts))*ISNUMBER(FIND("L",ts)), REPLACE(SUBSTITUTE(SUBSTITUTE(ts,"(",""),")",""),LEN(ts)-2,0,"-"),ts)))
 
Upvote 0
Hi Heathball, if (16.45l) was in B2 you could use =SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(B2,"(",""),")",""),"L","-L")
The first substitute finds the left bracket and replaces it with "" (nothing) =SUBSTITUTE( SUBSTITUTE( SUBSTITUTE(B2,"(","") ,")",""), "L","-L").
the 2nd substitute looks at the new data without the left bracket finds the right bracket and replaces it with "" (nothing) =SUBSTITUTE( SUBSTITUTE( SUBSTITUTE(B2,"(","") ,")",""), "L","-L").
The 3rd substitute looks at the new data without the left and right brackets, finds the "L" and replaces it with "-L" = SUBSTITUTE( SUBSTITUTE( SUBSTITUTE(B2,"(","") ,")",""), "L","-L").
Hope this helps
Hi,

Formula is OK but remove any bracket in that string if they are.
 
Upvote 0

Forum statistics

Threads
1,216,500
Messages
6,131,015
Members
449,615
Latest member
Nic0la

We've detected that you are using an adblocker.

We have a great community of people providing Excel help here, but the hosting costs are enormous. You can help keep this site running by allowing ads on MrExcel.com.
Allow Ads at MrExcel

Which adblocker are you using?

Disable AdBlock

Follow these easy steps to disable AdBlock

1)Click on the icon in the browser’s toolbar.
2)Click on the icon in the browser’s toolbar.
2)Click on the "Pause on this site" option.
Go back

Disable AdBlock Plus

Follow these easy steps to disable AdBlock Plus

1)Click on the icon in the browser’s toolbar.
2)Click on the toggle to disable it for "mrexcel.com".
Go back

Disable uBlock Origin

Follow these easy steps to disable uBlock Origin

1)Click on the icon in the browser’s toolbar.
2)Click on the "Power" button.
3)Click on the "Refresh" button.
Go back

Disable uBlock

Follow these easy steps to disable uBlock

1)Click on the icon in the browser’s toolbar.
2)Click on the "Power" button.
3)Click on the "Refresh" button.
Go back
Back
Top